document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154130>Question 154130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need the graph for this plotted out equation, please. Thank you!\r<BR>\n" );
document.write( "\n" );
document.write( "x + 2 = 2x - 1<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "the work is done, I only need the graph now. Thank you.\r<BR>\n" );
document.write( "\n" );
document.write( "x = 3<BR>\n" );
document.write( "Since there's no y term, no matter what y is, x is 3. You can make any 2 points and connect them.<BR>\n" );
document.write( "(3,0)<BR>\n" );
document.write( "(3,3)<BR>\n" );
document.write( "(3,-5)<BR>\n" );
document.write( "(3,200)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113434 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113434\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your reasoning so far is flawless!<BR>\n" );
document.write( "It should be apparent to you at this juncture that the graph of the equation, x = 3, is simply a vertical line passing through the points (3, y), where, as you succintly point out, y can be any value you choose. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );