document.write( "Question 154100: a person on a bike leaves an hour before a person on a motorcycle. the person on the bike is travelling at 10 mph. the person on the motorcycle is travelling at 40 mph. how long before the person on the motorcycle overtakes the person on the bike? \n" ); document.write( "
Algebra.Com's Answer #113420 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 10(X+1)=40X \n" ); document.write( "10X+10=40X \n" ); document.write( "10X-40X=-10 \n" ); document.write( "-30X=-10 \n" ); document.write( "X=-10/-30 \n" ); document.write( "X=.33 HOURS THE MOTORCYCLE WILL OVERTAKE THE BIKER. \n" ); document.write( " |