document.write( "Question 154107: A man rode a bicycle for 12 miles and then hiked on an additional 8 miles. The total time for the trip was 5 hr, if his rate when he was riding a bicycle was 10 miles per hour faster than his rate walking. What was each rate? \n" ); document.write( "
Algebra.Com's Answer #113418 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 5=12/(x+10)+8/x \n" ); document.write( "5=[12x+8(x+10)]/x(x+10) \n" ); document.write( "5=[12x+8x+80]/x^2+10x \n" ); document.write( "5=(20x+80)/x^2+10x \n" ); document.write( "5x^2+50x=20x+80 \n" ); document.write( "5x^2+50x-20x-80=0 \n" ); document.write( "5x^2+30x-80=0 \n" ); document.write( "5(x^2+6x-16)=0 \n" ); document.write( "5(x-2)(x+8)=0 \n" ); document.write( "x-2=0 \n" ); document.write( "x=2 mph for the hiking rate. \n" ); document.write( "10+2=12 mph for the biking rate. \n" ); document.write( "proof: \n" ); document.write( "5=12/12+8/2 \n" ); document.write( "5=1+4 \n" ); document.write( "5=5\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |