document.write( "Question 154051This question is from textbook
\n" ); document.write( ": Walking and Jogging: A student walks and jogs to college each day. She averages 5km/h walking and 9km/h jogging. The distance from the home to college is 8km, and she makes the trip in 1 hour. How far does the student jog? \n" ); document.write( "
Algebra.Com's Answer #113390 by orca(409)\"\" \"About 
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Let x be the distance the student jogs, the the distance the student walks is 8-x.
\n" ); document.write( "The time jogging is \"x%2F9\".
\n" ); document.write( "The time walking is \"%288-x%29%2F5\"
\n" ); document.write( "As the time jogging + the time walking = 1 hour, we have
\n" ); document.write( "\"x%2F9%2B%288-x%29%2F5=1\"
\n" ); document.write( "Solving for x, we have
\n" ); document.write( "\"45%28x%2F9%2B%288-x%29%2F5%29=1%2A45\" (multiply both sides by 45)\
\n" ); document.write( "\"5x+%2B9%288-x%29=45\"
\n" ); document.write( "\"5x%2B72-9x=45\"
\n" ); document.write( "\"-4x=-27\"
\n" ); document.write( "\"x+=+27%2F4\"
\n" ); document.write( "so the student jogs \"27%2F4\" miles.
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