document.write( "Question 154017: Walt made an extra $9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of $770 in interest. How much was invested at 8%. \r
\n" ); document.write( "\n" ); document.write( "I believe the answer to be $4000 invested at 8% because
\n" ); document.write( "$4000x.08=$320 and $5000x.09=$450 so $320+$450=$770. I Cannot however figure out how to put this in a linear equation. Please help.
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Algebra.Com's Answer #113364 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
.09x+.08(9000-x)=770
\n" ); document.write( ".09x+720-.08x=770
\n" ); document.write( ".01x=770-720
\n" ); document.write( ".01x=50
\n" ); document.write( "x=50/.01
\n" ); document.write( "x=$5,000 amount invested @ 9%
\n" ); document.write( "9000-5000=$4,000 amount invested @ 8%
\n" ); document.write( "proof:
\n" ); document.write( ".09*5000+.08*4000=770
\n" ); document.write( "450+320=770
\n" ); document.write( "770=770
\n" ); document.write( "
\n" );