document.write( "Question 154017: Walt made an extra $9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of $770 in interest. How much was invested at 8%. \r
\n" );
document.write( "\n" );
document.write( "I believe the answer to be $4000 invested at 8% because
\n" );
document.write( "$4000x.08=$320 and $5000x.09=$450 so $320+$450=$770. I Cannot however figure out how to put this in a linear equation. Please help. \n" );
document.write( "
Algebra.Com's Answer #113364 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .09x+.08(9000-x)=770 \n" ); document.write( ".09x+720-.08x=770 \n" ); document.write( ".01x=770-720 \n" ); document.write( ".01x=50 \n" ); document.write( "x=50/.01 \n" ); document.write( "x=$5,000 amount invested @ 9% \n" ); document.write( "9000-5000=$4,000 amount invested @ 8% \n" ); document.write( "proof: \n" ); document.write( ".09*5000+.08*4000=770 \n" ); document.write( "450+320=770 \n" ); document.write( "770=770 \n" ); document.write( " |