document.write( "Question 153960: Ryan drives to Pittsburgh at 55 mph and returns by a road 10 miles shorter at 60 mph. The return trip takes 30 minutes less. How long is each road? \n" ); document.write( "
Algebra.Com's Answer #113340 by ankor@dixie-net.com(22740)\"\" \"About 
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Ryan drives to Pittsburgh at 55 mph and returns by a road 10 miles shorter at 60 mph. The return trip takes 30 minutes less. How long is each road?
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\n" ); document.write( "let d = distance of the original trip
\n" ); document.write( "then
\n" ); document.write( "(d-10) = distance of the return trip
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\n" ); document.write( "Convert 30 min to hrs; .5 hrs
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\n" ); document.write( "Write a time equation:
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\n" ); document.write( "to time = return time + one-half hr
\n" ); document.write( "\"d%2F55\" = \"%28%28d-10%29%29%2F60\" + .5
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\n" ); document.write( "Multiply equation by 3300 to get rid of the denominator (55*60)
\n" ); document.write( "60d = 55(d-10) + 3300(.5)
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\n" ); document.write( "60d = 55d - 550 + 1650
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\n" ); document.write( "60d - 55d = 1100
\n" ); document.write( "d = \"1100%2F5\"
\n" ); document.write( "d = 220 mile is the original trip and 210 miles is the return trip
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\n" ); document.write( "Check solution by finding the time for each trip
\n" ); document.write( "220/55 = 4 hrs
\n" ); document.write( "210/60 = 3.5 hrs
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