document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=153938>Question 153938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I dont understand this question....\r<BR>\n" );
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document.write( "3v^3 - 6v^2 + 2v - 4\r<BR>\n" );
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document.write( "My teacher would like me to factor each completely.... I dont understand how to do this problem..... please get back to me asap </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113321 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> reducing this to a quadratic by finding a root is one way to factor\r<BR>\n" );
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document.write( "possible roots are factors of 4 (±1,±2,±4) divided by factors of 3 (±1,±3)<BR>\n" );
document.write( "__ a root is a value for v that makes the expression equal to zero\r<BR>\n" );
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document.write( "2 is a root __ 3(2^3)-6(2^2)+2(2)-4=0\r<BR>\n" );
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document.write( "if 2 is a root, then v-2 is a factor\r<BR>\n" );
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document.write( "(3v^3-6v^2+2v-4)/(v-2)=(3v^2+2) __ this will not factor further\r<BR>\n" );
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document.write( "so, 3v^3-6v^2+2v-4=(v-2)(3v^2+2) </SPAN>\n" );
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