document.write( "Question 153919: 5 + 5/6 + 5/6^2 + 5/6^3+...\r
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Algebra.Com's Answer #113294 by Edwin McCravy(20059)\"\" \"About 
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\"5+%2B+5%2F6+%2B+5%2F6%5E2+%2B+5%2F6%5E3%2B...\"
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document.write( "The formula is \r\n" );
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document.write( "\"S%5Binfinity%5D+=+a%5B1%5D%2F%281-r%29\",\r\n" );
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document.write( "where \"a%5B1%5D+=+FIRST_TERM+=+5\"\r\n" );
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document.write( "To find r, divide the second term \"a%5B2%5D\" or \"5%2F6\" \r\n" );
document.write( "by the first term \"a%5B1%5D\" or \"5\":\r\n" );
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document.write( "\"r=5%2F6\"÷\"5\" = \"5%2F6\"÷\"5%2F1\" = \"5%2F6\"×\"1%2F5\" = \"cross%285%29%2F6\"×\"1%2Fcross%285%29\" = \"1%2F6\"\r\n" );
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document.write( "Plug in:\r\n" );
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document.write( "\"S%5Binfinity%5D+=+a%5B1%5D%2F%281-r%29\"\r\n" );
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document.write( "\"S%5Binfinity%5D+=+5%2F%281-1%2F6%29\"\r\n" );
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document.write( "\"S%5Binfinity%5D+=+5%2F%286%2F6-1%2F6%29\",\r\n" );
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document.write( "\"S%5Binfinity%5D+=+5%2F%285%2F6%29\",\r\n" );
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document.write( "\"S%5Binfinity%5D+=+%285%2F1%29%2F%285%2F6%29\",\r\n" );
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document.write( "\"S%5Binfinity%5D+=+5%2F1\"÷\"5%2F6\"\r\n" );
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document.write( "\"S%5Binfinity%5D+=+5%2F1\"×\"6%2F5\"\r\n" );
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document.write( "\"S%5Binfinity%5D+=+cross%285%29%2F1\"×\"6%2Fcross%285%29\"\r\n" );
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document.write( "\"S%5Binfinity%5D+=+6\"\r\n" );
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document.write( "Edwin
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