document.write( "Question 153882: An airplane left an airport flying at at 180 mph. A jet that flies at 333 mph left 1 hour later. The jet follows tthe same route as the airplane on parallel altitudes. How many hours will it take the jet to catch up with the airplane? \n" ); document.write( "
Algebra.Com's Answer #113282 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! An airplane left an airport flying at at 180 mph. A jet that flies at 333 mph left 1 hour later. The jet follows tthe same route as the airplane on parallel altitudes. How many hours will it take the jet to catch up with the airplane? \n" ); document.write( ". \n" ); document.write( "This problem needs you to apply the \"distance formula\": \n" ); document.write( "d = rt \n" ); document.write( "where \n" ); document.write( "d is distance \n" ); document.write( "r is rate or speed \n" ); document.write( "t is time \n" ); document.write( ". \n" ); document.write( "\"distance airplane traveled\" = \"distnce jet traveled\" \n" ); document.write( ". \n" ); document.write( "Let x = hours \"airplane\" was flying \n" ); document.write( "x-1 = hours \"jet\" was flying \n" ); document.write( ". \n" ); document.write( "180x = 333(x-1) \n" ); document.write( "180x = 333x - 333 \n" ); document.write( "180x + 333 = 333x \n" ); document.write( "333 = 153x \n" ); document.write( "333/153 = x \n" ); document.write( "2.176 hours = x \n" ); document.write( ".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |