document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=153884>Question 153884</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two jets leave Dallas and fly in opposite directions.  One is flying 50 mph faster than the other.  After 2 hours they are 2500 miles apart.  Find the speed of each jet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113250 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the speed of the slower jet.<BR>\n" );
document.write( "Then the speed of the faster one is x + 50.<BR>\n" );
document.write( "The distance that separating them at the end of 2 hours can be expressed in terms of x as:<BR>\n" );
document.write( "2x + 2(x + 50)<BR>\n" );
document.write( "As the separating distance is 2500, we have<BR>\n" );
document.write( "2x + 2(x + 50) = 2500<BR>\n" );
document.write( "Solving for x, we have<BR>\n" );
document.write( "2x + 2x +100 = 2500<BR>\n" );
document.write( "4x = 2400<BR>\n" );
document.write( "x = 600<BR>\n" );
document.write( "So the speed of the slower jet is 600 miles per hour<BR>\n" );
document.write( "the speed of the fast jet is x + 50 = 650 miles per hour. </SPAN>\n" );
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