document.write( "Question 153865: Find two consecutive integers such that the sum of the first and 3 times the second is 55. \n" ); document.write( "

Algebra.Com's Answer #113246 by orca(409) $\"\"$ $\"About$

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Let the two consecutive numbers be n, n+ 1.
\n" ); document.write( "The sum of the first and 3 times the second can be expressed as
\n" ); document.write( "n + 3(n + 1)
\n" ); document.write( "Setting it equal to 55, we have
\n" ); document.write( "n + 3(n + 1) = 55
\n" ); document.write( "Solving for x, we have
\n" ); document.write( "n + 3n + 3 = 55
\n" ); document.write( "4n + 3 = 55
\n" ); document.write( "4n = 52
\n" ); document.write( "n = 13
\n" ); document.write( "So the two consecutive numbers are 13 and 14.
\n" ); document.write( " \n" ); document.write( "

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