document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22912>Question 22912</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ((x-2)/(x-1))+((x-3)/(2x-5))=1<BR>\n" );
document.write( "I was told to solve this equation but im having a heck of a time.  The whole =1 thing is killin me and throwing me way off.  Please help if you can. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11324 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ((x-2)/(x-1))+((x-3)/(2x-5))=1<BR>\n" );
document.write( "LCM IS (X-1)(2X-5)..SO MULTIPLY THROUGHOUT WITH THE LCM ..WE GET..<BR>\n" );
document.write( "(x-2)(2x-5)+(x-3)(x-1)=(x-1)(2x-5)<BR>\n" );
document.write( "2x^2-5x-4x+10+x^2-x-3x+3=2x^2-5x-2x+5<BR>\n" );
document.write( "2x^2-5x-4x+10+x^2-x-3x+3-2x^2+5x+2x-5=0<BR>\n" );
document.write( "x^2-6x+8=0<BR>\n" );
document.write( "x^2-4x-2x+8=0<BR>\n" );
document.write( "x(x-4)-2(x-4)=0<BR>\n" );
document.write( "(x-2)(x-4)=0<BR>\n" );
document.write( "x-2=0....or....x-4=0<BR>\n" );
document.write( "x=2....or.....4<BR>\n" );
document.write( "you can check back by substitution<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );