document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=153864>Question 153864</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose you have a coin collection of nickels and dimes containing 63 coins. If you have $5.05, how many of each type of coin do you have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113233 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose you have a coin collection of nickels and dimes containing 63 coins. If you have $5.05, how many of each type of coin do you have?<BR>\n" );
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document.write( "EQUATIONS:<BR>\n" );
document.write( "quantity: n + d = 63<BR>\n" );
document.write( "value:   5n + 10d = 505<BR>\n" );
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document.write( "Divide thru the 2nd equation by 5 to get:<BR>\n" );
document.write( "n + 2d = 101<BR>\n" );
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document.write( "Subtract that from the 1st equation:<BR>\n" );
document.write( "-d = -38<BR>\n" );
document.write( "d = 38 (# of dimes)<BR>\n" );
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document.write( "Substitute that into n+d=63 to solve for \"n\":<BR>\n" );
document.write( "n + 38 = 63<BR>\n" );
document.write( "n = 25 (# of nickels)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );