document.write( "Question 22957: Please help me, i had a hard time to answer these questions. Thank you! Here it goes, how much water must be evaporated from 18 kilograms of a 20% salt solution to produce a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #11323 by rapaljer(4671) You can put this solution on YOUR website! Let x = amount of water evaporated \n" ); document.write( "18 = amount of liquid before \n" ); document.write( "18-x = amount of liquid after\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Amount of salt before = Amount of salt after \n" ); document.write( ".20*18= .50(18-x) \n" ); document.write( "3.6 = 9.0 - .5x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 9.0 from each side \n" ); document.write( "3.6 - 9.0 = 9.0 - 9.0 - .5x \n" ); document.write( "-5.4 = -.5x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by -.5: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x= 10.8 liters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( ".2* 18 = 3.6 before \n" ); document.write( ".5*(18-10.8)= .5(7.2)= 3.6 after\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |