document.write( "Question 22957: Please help me, i had a hard time to answer these questions. Thank you! Here it goes, how much water must be evaporated from 18 kilograms of a 20% salt solution to produce a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #11323 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let x = amount of water evaporated
\n" ); document.write( "18 = amount of liquid before
\n" ); document.write( "18-x = amount of liquid after\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Amount of salt before = Amount of salt after
\n" ); document.write( ".20*18= .50(18-x)
\n" ); document.write( "3.6 = 9.0 - .5x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Subtract 9.0 from each side
\n" ); document.write( "3.6 - 9.0 = 9.0 - 9.0 - .5x
\n" ); document.write( "-5.4 = -.5x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Divide by -.5:
\n" ); document.write( "\"%28-5.4%29%2F%28-.5%29+=+%28-.5x%29%2F%28-.5%29\"
\n" ); document.write( "\"10.8+=+x+\"
\n" ); document.write( "x= 10.8 liters\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( ".2* 18 = 3.6 before
\n" ); document.write( ".5*(18-10.8)= .5(7.2)= 3.6 after\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );