document.write( "Question 153862: John is 4 years younger than her brother. Five years from now, the sum of their ages will be 32. Find John's present age. \n" ); document.write( "
Algebra.Com's Answer #113226 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! John is 4 years younger than her brother. Five years from now, the sum of their ages will be 32. Find John's present age. \n" ); document.write( "------------------- \n" ); document.write( "John's a girl? \n" ); document.write( "J = John's age \n" ); document.write( "B = brother's age \n" ); document.write( "---------------- \n" ); document.write( "John is 4 years younger than her brother. \n" ); document.write( "So, B = J + 4 eqn 1 \n" ); document.write( "-------------- \n" ); document.write( "Five years from now, the sum of their ages will be 32. \n" ); document.write( "(J+5) + (B+5) = 32 \n" ); document.write( "J + B = 22 eqn 2 \n" ); document.write( "Substitute for B from eqn 1 \n" ); document.write( "J + (J + 4) = 22 \n" ); document.write( "2J + 4 = 22 \n" ); document.write( "2J = 18 \n" ); document.write( "J = 9 \n" ); document.write( "B = 9+4 \n" ); document.write( "B = 13\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |