document.write( "Question 153862: John is 4 years younger than her brother. Five years from now, the sum of their ages will be 32. Find John's present age. \n" ); document.write( "
Algebra.Com's Answer #113226 by Alan3354(69443)\"\" \"About 
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John is 4 years younger than her brother. Five years from now, the sum of their ages will be 32. Find John's present age.
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\n" ); document.write( "John's a girl?
\n" ); document.write( "J = John's age
\n" ); document.write( "B = brother's age
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\n" ); document.write( "John is 4 years younger than her brother.
\n" ); document.write( "So, B = J + 4 eqn 1
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\n" ); document.write( "Five years from now, the sum of their ages will be 32.
\n" ); document.write( "(J+5) + (B+5) = 32
\n" ); document.write( "J + B = 22 eqn 2
\n" ); document.write( "Substitute for B from eqn 1
\n" ); document.write( "J + (J + 4) = 22
\n" ); document.write( "2J + 4 = 22
\n" ); document.write( "2J = 18
\n" ); document.write( "J = 9
\n" ); document.write( "B = 9+4
\n" ); document.write( "B = 13\r
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