document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2620>Question 2620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find two numbers whose sum is 50and whose product is a maximum </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1131 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Let x be one of them,another is 50-x,\r<BR>\n" );
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document.write( " their product f(x) = x(50-x) = -(x^2-50x+(50/2)^2) +625 <BR>\n" );
document.write( "  = 625 -(x-25)^2  [Use complete square]<BR>\n" );
document.write( " Since -(x-25)^2 <=0, f(x) <= 625.<BR>\n" );
document.write( " when x = 25, f(x) has max value 625.\r<BR>\n" );
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document.write( " Thus, when the two numbers are 25, 25(in fact equal), their<BR>\n" );
document.write( " procudt is max(vale 625).\r<BR>\n" );
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document.write( " Kenny </SPAN>\n" );
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