document.write( "Question 153575: line perpendicular to x-2y=24 and passing through (1,-3) \n" ); document.write( "
Algebra.Com's Answer #113049 by nerdybill(7384)\"\" \"About 
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line perpendicular to x-2y=24 and passing through (1,-3)
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\n" ); document.write( "First, rearrange your expression to the \"slope intercept\" form:
\n" ); document.write( "y = mx + b
\n" ); document.write( "where
\n" ); document.write( "m is slope
\n" ); document.write( "b is the y-intercept
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\n" ); document.write( "Your equation:
\n" ); document.write( "x-2y=24
\n" ); document.write( "-2y = -x + 24
\n" ); document.write( "y = (1/2)x - 12
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\n" ); document.write( "Now, we know that the \"slope\" (m) of
\n" ); document.write( "x-2y=24
\n" ); document.write( "is 1/2
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\n" ); document.write( "A line perpendicular to the above MUST be the negative reciprocal:
\n" ); document.write( "If our new slope is M then:
\n" ); document.write( "(1/2)M = -1
\n" ); document.write( "M = -2
\n" ); document.write( "Therefore, our NEW line has a slope (m) of -2
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\n" ); document.write( "Recapping:
\n" ); document.write( "We now know our new line has
\n" ); document.write( "slope (m) = -2
\n" ); document.write( "AND
\n" ); document.write( "it passes through:
\n" ); document.write( "(1,-3)
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\n" ); document.write( "Plug the above back into the \"slope intercept\" form and solve for 'b':
\n" ); document.write( "y = mx + b
\n" ); document.write( "-3 = (-2)(1) + b
\n" ); document.write( "-3 = -2 + b
\n" ); document.write( "-1 = b
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\n" ); document.write( "We NOW know:
\n" ); document.write( "b = -1
\n" ); document.write( "m = (1/2)
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\n" ); document.write( "Plugging it into:
\n" ); document.write( "y = mx + b
\n" ); document.write( "y = (1/2)x + (-1)
\n" ); document.write( "or
\n" ); document.write( "y = (1/2)x - 1 (this is your answer!)\r
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