document.write( "Question 153414: Sam has 3000 feet of fencting available to enclose a rectangular field\r
\n" ); document.write( "\n" ); document.write( "a) Express the area A of the rectangle as a function of x where x is the length of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "b) For what value of x is the area largest?\r
\n" ); document.write( "\n" ); document.write( "c) What is the maximum area?
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Algebra.Com's Answer #112966 by orca(409)\"\" \"About 
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First we need to express the width of the rectangle in terms of x.
\n" ); document.write( "The perimeter of the rectangle is:
\n" ); document.write( "Perimeter = 2*length + 2*width.
\n" ); document.write( "So width = (perimeter - 2*length)/2
\n" ); document.write( "Substituting length = x and perimeter = 3000, we have:
\n" ); document.write( "\"width+=+%283000-2x%29%2F2=1500-x\"
\n" ); document.write( "So the area of the rectangle is
\n" ); document.write( "\"A=length%2Awidth\"
\n" ); document.write( "=\"x%2A%281500-x%29\"
\n" ); document.write( "=\"1500x-x%5E2%29\"
\n" ); document.write( "To find the maximum value of the quadratic expression, we can use either the formula or the completing square method. Here the second method is used.
\n" ); document.write( "\"A+=+1500x-x%5E2\"
\n" ); document.write( "=\"-x%5E2%2B1500x\"
\n" ); document.write( "=\"-%28x%5E2-1500x%29\"
\n" ); document.write( "=\"-%28x%5E2-2%2A750x%29\"
\n" ); document.write( "=\"-%28x%5E2-2%2A750x%2B750%5E2-750%5E2%29\"
\n" ); document.write( "=\"-%28%28x%5E2-2%2A750x%2B750%5E2%29-750%5E2%29\"
\n" ); document.write( "=\"-%28%28x-750%29%5E2-750%5E2%29\"
\n" ); document.write( "=\"-%28x-750%29%5E2%2B750%5E2\"
\n" ); document.write( "=\"750%5E2-%28x-750%29%5E2\"
\n" ); document.write( "\"750%5E2-%28x-750%29%5E2\" has maximum value \"750%5E2\" when \"%28x-750%29%5E2=0\".
\n" ); document.write( "For \"%28x-750%29%5E2=0\", x must be equal to 750.
\n" ); document.write( "So when x = 750, A has the maximum value \"750%5E2\".
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