document.write( "Question 153445: a bicyclist and a hiker leave the same place at the same time and travel in the same direction.the bicyclist travels 3 times as fast as the hiker.at the end of 3 hours they are 24 miles apart.how fast does the hiker travel? \n" ); document.write( "
Algebra.Com's Answer #112949 by jojo14344(1513)\"\" \"About 
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Remember:
\n" ); document.write( "\"speed=x%28mi%2Fhr%29\" of the bicyclist and hiker:
\n" ); document.write( "\"hiker=h=x%28mi%2Fhr%29\"
\n" ); document.write( "\"biker=b=3x%28mi%2Fhr%29\", 3 times faster
\n" ); document.write( "Equating the 2 speeds and adding the speed (separation) of 24 miles in 3 hours to the hiker since the bicyclist is faster than the hiker:
\n" ); document.write( "\"hiker=biker\"
\n" ); document.write( "\"%28x%28mi%2Fhr%29%29+%2B%2824mi%2F3hr%29=3x%28mi%2Fhr%29\"
\n" ); document.write( "\"%28cross%2824%298mi%2Fcross%283%29hr%29=3x%28mi%2Fhr%29-x%28mi%2Fhr%29\"
\n" ); document.write( "\"8%28mi%2Fhr%29=2x%28mi%2Fhr%29\" ----> \"cross%288%294%28mi%2Fhr%29=cross%282%29x%28mi%2Fhr%29\"
\n" ); document.write( "\"x=4%28mi%2Fhr%29\" ---------------------> speed of the hiker
\n" ); document.write( "For bicyclist:
\n" ); document.write( "\"3%2A4=12%28mi%2Fhr%29\" ------------------> speed of the bicyclist
\n" ); document.write( "to check, lets calculate the distance in 3 hours:
\n" ); document.write( "hiker: \"4%28mi%2Fcross%28hour%29%29%283cross%28hours%29%29=12miles\"
\n" ); document.write( "biker: \"12%28mi%2Fcross%28hour%29%29%283cross%28hours%29%29=36miles\"
\n" ); document.write( "IT'S TRUE THAT AFTER 3 HOURS, THE DISTANCE SEPARATING THEM IS \"36-12=24miles\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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