document.write( "Question 153428: I have a few questions like these in my college algebra book with no examples to help.\r
\n" ); document.write( "\n" ); document.write( "10-13/x=4+5/x\r
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "x/(x+4) + 4/(x+4) + 2= 0
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Algebra.Com's Answer #112932 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"10-13%2Fx+=+4+%2B+5%2Fx\" Multiply both sides by x.
\n" ); document.write( "\"10x-13+=+4x%2B5\" Subtract 4x from both sides.
\n" ); document.write( "\"6x-13+=+5\" Add 13 to both sides.
\n" ); document.write( "\"6x+=+18\" Finally, divide both sides by 6.
\n" ); document.write( "\"x+=+3\"
\n" ); document.write( "---------------
\n" ); document.write( "\"x%2F%28x%2B4%29+%2B+4%2F%28x%2B4%29+%2B+2+=+0\" Multiply through by (x+4)
\n" ); document.write( "\"x%2B4%2B2%28x%2B4%29+=+0\" Expand the last term.
\n" ); document.write( "\"x%2B4%2B2x%2B8+=+0\" Combine like-terms.
\n" ); document.write( "\"3x%2B12+=+0\" Subtact 12 from both sides.
\n" ); document.write( "\"3x+=+-12\" Finally, divide both sides by 3.
\n" ); document.write( "\"x+=+-4\"
\n" ); document.write( "The only problem with this solution is that it is x = -4 is an excluded value.
\n" ); document.write( "Why? Because, when you substitute x = -4 into the original equation, the first two terms are undefined:
\n" ); document.write( "\"-4%2F%28-4%2B4%29+%2B+4%2F%28-4%2B4%29+%2B+2+=+0\"
\n" ); document.write( "\"%28-4%29%2F0+%2B+4%2F0+%2B+2+=+0\" As you can see, the first two terms are undefined because division by zero is not defined.
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