document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=153401>Question 153401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if it takes you 6 hours to run four loads with omly one washer, how long would it yake to run the same at the laudromat using 3 washers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112923 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if it takes you 6 hours to run four loads with only one washer, <BR>\n" );
document.write( "Each load takes 6/4 = 3/2 hr per washer<BR>\n" );
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document.write( "how long would it take to run the same at the laudromat using 3 washers?<BR>\n" );
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document.write( "(# of loads)/(# of washers)k = (# of hours)<BR>\n" );
document.write( "(4/1)k = 6<BR>\n" );
document.write( "k = 3/2<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "(# of loads)/(# of washers)(3/2) = # of hours<BR>\n" );
document.write( "(4) /( 3) (3/2) = # of hours<BR>\n" );
document.write( "4/2 = # of hours<BR>\n" );
document.write( "2 = # of hours<BR>\n" );
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document.write( "Ans: In 2 hours, 3 washers can do 4 loads.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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