document.write( "Question 153368: Please help me solve the following problem:
\n" ); document.write( "Rewrite the expression using positive exponents. \"%28%28-2%29%5E0%29%283x%5E-2%28y%5E-2%29%29%5E-1\"
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Algebra.Com's Answer #112892 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Rewrite, using positive exponents:
\n" ); document.write( "\"%28%28-2%29%5E0%29%2A%283x%5E%28-2%29%28y%5E%28-2%29%29%29%5E%28-1%29\"
\n" ); document.write( "First, anything to the zero power is equal to 1 \"x%5E0+=+1\", so \"%28-2%29%5E0+=+1\", so now you have:
\n" ); document.write( "\"1%2A%283x%5E%28-2%29%2A%28y%5E%28-2%29%29%29%5E%28-1%29\" You can remove the inner parentheses as they are not needed.
\n" ); document.write( "\"%283x%5E%28-2%29%2Ay%5E%28-2%29%29%5E%28-1%29\" To raise an exponent to a power, you multiply the exponents. \"%28-1%29%2A%28-2%29+=+2\"
\n" ); document.write( "\"3x%5E2%2Ay%5E2%29\"
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