document.write( "Question 153352This question is from textbook elementary and intermediate algebra concepts and applications
\n" ); document.write( ": Can I please get some help solving these
\n" ); document.write( " Solve by substitution or elimination method:
\n" ); document.write( " -4x + 3y = 5
\n" ); document.write( " 12x - 9y = -15
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Algebra.Com's Answer #112879 by jim_thompson5910(35256)\"\" \"About 
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"-4%2Ax%2B3%2Ay=5\"
\n" ); document.write( " \"12%2Ax-9%2Ay=-15\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get -4 and 12 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of -4 and 12 is -12, we need to multiply both sides of the top equation by 3 and multiply both sides of the bottom equation by 1 like this:
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\n" ); document.write( " \"3%2A%28-4%2Ax%2B3%2Ay%29=%285%29%2A3\" Multiply the top equation (both sides) by 3
\n" ); document.write( " \"1%2A%2812%2Ax-9%2Ay%29=%28-15%29%2A1\" Multiply the bottom equation (both sides) by 1
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"-12%2Ax%2B9%2Ay=15\"
\n" ); document.write( " \"12%2Ax-9%2Ay=-15\"
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\n" ); document.write( " Notice how -12 and 12 add to zero, 9 and -9 add to zero, 15 and -15 and to zero (ie \"-12%2B12=0\") \"9%2B-9=0\", and \"15%2B-15=0\")
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\n" ); document.write( " So we're left with
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\n" ); document.write( " \"0=0\"
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\n" ); document.write( " which means any x or y value will satisfy the system of equations. So there are an infinite number of solutions
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\n" ); document.write( " So this system is dependent
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