document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=153324>Question 153324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112871 by </B><A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><B>mangopeeler07(462)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=number of dimes<BR>\n" );
document.write( "n=number of nickels<BR>\n" );
document.write( "coefficient= value of the coin\r<BR>\n" );
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document.write( "value of dime(number of dimes)+value of nickel(number of nickels)=total value<BR>\n" );
document.write( "10(d)+5(n)=565\r<BR>\n" );
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document.write( "10(2d)+5(n+8)=1045------------If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45.\r<BR>\n" );
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document.write( "Distribute<BR>\n" );
document.write( "20d+5n+40=1045\r<BR>\n" );
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document.write( "Subtract 40 from both sides<BR>\n" );
document.write( "20d+5n=1005<BR>\n" );
document.write( "and<BR>\n" );
document.write( "10d+5n=565 both have 5n, so subtract them from each other\r<BR>\n" );
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document.write( "10d=440\r<BR>\n" );
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document.write( "Divide both sides by 10<BR>\n" );
document.write( "d=44\r<BR>\n" );
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document.write( "Number of dimes=44 </SPAN>\n" );
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