document.write( "Question 153306: A snack food is made by mixing 5 lbs. of popcorn that costs $.80 per pound with caramel that costs $2.40 per pound. How much caramel is needed to make a mixture that costs $1.40 per pound? \n" ); document.write( "
Algebra.Com's Answer #112844 by mangopeeler07(462)\"\" \"About 
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A snack food is made by mixing 5 lbs. of popcorn that costs $.80 per pound with caramel that costs $2.40 per pound. How much caramel is needed to make a mixture that costs $1.40 per pound?\r
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\n" ); document.write( "\n" ); document.write( "5=lbs of popcorn
\n" ); document.write( "c=lbs of caramel
\n" ); document.write( "80=cost per pound of popcorn (in cents)
\n" ); document.write( "240=cost per pound of caramel (in cents)
\n" ); document.write( "140=cost of both together (in cents)\r
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\n" ); document.write( "\n" ); document.write( "cost(lbs popcorn)+cost(lbs caramel)=cost(lbs popcorn and caramel)
\n" ); document.write( "80(5)+240(c)=140(5+c)\r
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\n" ); document.write( "\n" ); document.write( "400+240c=700+140c\r
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\n" ); document.write( "\n" ); document.write( "Subtract 400 from both sides
\n" ); document.write( "240c=300+140c\r
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\n" ); document.write( "\n" ); document.write( "Subtract 140c from both sides
\n" ); document.write( "100c=300\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 100
\n" ); document.write( "c=3\r
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\n" ); document.write( "\n" ); document.write( "Answer: 3 lbs of caramel
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