document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=153279>Question 153279</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395771188/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Larry has an annual return of $213 from $3000 invested at simple interest, some at 5% and the rest a8%. How much is invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112812 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount invested at 5%, then the amount invested at 8% was 3000 - x.<BR>\n" );
document.write( "The total interest earned from the two investments can be expressed in terms of x as:<BR>\n" );
document.write( "5%x + 8%(3000-x)<BR>\n" );
document.write( "Setting it equal 213, we have<BR>\n" );
document.write( "5%x + 8%(3000-x)=213<BR>\n" );
document.write( "Solving for x, we obtain<BR>\n" );
document.write( "5x + 8(3000 - x) = 21300      (multiply both sides by 100)<BR>\n" );
document.write( "5x + 24000 - 8x = 21300<BR>\n" );
document.write( "-3x = -2700<BR>\n" );
document.write( "x = (-2700)/(-3)<BR>\n" );
document.write( "x = 2700/3<BR>\n" );
document.write( "x = 900<BR>\n" );
document.write( "So Larry invested $900 at 5%,and $2,100 at 8%.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );