document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22895>Question 22895</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One leg of a right triangle is 4cm shorter thatn the other leg. The length of the hypotenuse is 20 cm. Find the length of the shorter leg.<BR>\n" );
document.write( "A. 16cm<BR>\n" );
document.write( "B. 17cm<BR>\n" );
document.write( "C. 13cm<BR>\n" );
document.write( "D. 12cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11281 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11281\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Right triangle formula is a^2 + b^2 = c^2.\r<BR>\n" );
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document.write( "(x)^2 + (x-4)^2 = (20)^2<BR>\n" );
document.write( "x^2 + x^2 -8x +16 = 400<BR>\n" );
document.write( "2x^2 -8x + 16 = 400<BR>\n" );
document.write( "2(x^2-4x+8) = 400<BR>\n" );
document.write( "x^2-4x+8 = 200<BR>\n" );
document.write( "x^2-4x-192 = 0<BR>\n" );
document.write( "(x-16)(x+12) =0\r<BR>\n" );
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document.write( "The solutions for x are 16 and -12.  We can ignore the -12 answer. So, x=16 and the shorter leg is x-4 or 12.\r<BR>\n" );
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document.write( "I hope that you were able to follow the solution. </SPAN>\n" );
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