document.write( "Question 22602: If f(x)=3x+11, what is the value of (f^-1 o f)(2)....I don't even know where to start on this one!!! \n" ); document.write( "
Algebra.Com's Answer #11280 by venugopalramana(3286)\"\" \"About 
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If f(x)=3x+11, what is the value of (f^-1 o f)(2)....I don't even know where to start on this one!!!
\n" ); document.write( "LET ME TELL YOU FEW THINGS FIRST...IF
\n" ); document.write( "F(X)=3X+11...THEN F(2) MEANS PUT 2 INPLACE OF X ...YOU GET F(2)=3*2+11=17
\n" ); document.write( "F^-1(X) MEANS LIKE THIS ..CALL Y=F(X)=3X+11 AS GIVEN ..THEN YOU HAVE TO FIND X INTERMS OF Y.AS WE HAVE 3X=Y-11
\n" ); document.write( "X=(Y-11)/3...THIS FUNCTION (Y-11)/3 IS CALLED F^-1(X) = F(Y)=(Y-11)/3
\n" ); document.write( "SO F(X) AND F^-1(X ARE INVERSE PROCESSES.SO IF YOU APPLY BOTH TO SOME X YOU GET BACK X..THAT IS F^-1 OF F(X)=X..LET US CJHECK WITH OUR EXAMPLE..
\n" ); document.write( "F(X)=3X+11..SO F^-1{3X+11)= {PUT 3X+11 IN PLACE OF Y SINCE F^-1(X)=F(Y)=(Y-11)/3
\n" ); document.write( "..SO WE GET (3X+11-11)/3=3X/3=X......\r
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\n" ); document.write( "\n" ); document.write( "IN THE PRESENT PROBLEM.....
\n" ); document.write( "F(X)=3X+11....SO F(2)=3*2+11=17
\n" ); document.write( "F^-1(X)=F(Y)=(Y-11)/3....SO F^-1(F(2))=F^-1(17)=(17-11)/3=6/3=2...SO WE GET BACK OUR X=2 AS THE ANSWER AS PROVED ABOVE....
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