document.write( "Question 153251: 4x^2/3-27x^1/3-7=0 \n" ); document.write( "
Algebra.Com's Answer #112788 by stanbon(75887)\"\" \"About 
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4x^2/3-27x^1/3-7=0
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\n" ); document.write( "Let x^(1/3) = w
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\n" ); document.write( "Substitute to get:
\n" ); document.write( "4w^2 - 27w - 7 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "4w^2-28w+w-7 = 0
\n" ); document.write( "4w(w-7)+(w-7) = 0
\n" ); document.write( "(w-7)(4w+1) = 0
\n" ); document.write( "w = 7 or w = -1/4
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\n" ); document.write( "Substitute to get:
\n" ); document.write( "x^(1/3) = 7 or x^(1/3) = -1/4
\n" ); document.write( "x = 7^3 = 343 or x = -1/64
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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