document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22646>Question 22646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fully factor the third-order polynomial H(s) if it is known that one of the factors is (s+2). <BR>\n" );
document.write( "H(s)= 2s^3-7s^2-43s-42 <BR>\n" );
document.write( "I need help....  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11278 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11278\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> H(s)= 2s^3-7s^2-43s-42 try s=0,1,2,-1,-2 etc..<BR>\n" );
document.write( "we find that at s=2 ....H=0...HENCE S+2 IS A FACTOR<BR>\n" );
document.write( "DIVIDING WITH S+2 WE GET<BR>\n" );
document.write( "-2...|...2......-7.........-43.........-42<BR>\n" );
document.write( ".....|...0......-4..........22..........42<BR>\n" );
document.write( "..............................................<BR>\n" );
document.write( ".........2......-11.........-21..........0<BR>\n" );
document.write( "HENCE WE GET 2S^2-11S-21<BR>\n" );
document.write( "=2S^2-14S+3S-21=2S(S-7)+3(S-7)=(2S+3)(S-7)..HENCE <BR>\n" );
document.write( "H(S)=(S+2)(2S+3)(S-7)<BR>\n" );
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