document.write( "Question 153236: The manager at Cream of the Crop bought a load of watermelons for $200. She priced the melons so that she would make $1.50 profit for each melon. When all but 30 had been sold, the manager had recovered her initial investment. How many did she buy originally? \n" ); document.write( "
Algebra.Com's Answer #112776 by stanbon(75887)\"\" \"About 
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The manager at Cream of the Crop bought a load of watermelons for $200. She priced the melons so that she would make $1.50 profit for each melon. When all but 30 had been sold, the manager had recovered her initial investment. How many did she buy originally?
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\n" ); document.write( "Let the original number bought be \"x\".
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\n" ); document.write( "Average cost of each melon was $(200/x)
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\n" ); document.write( "She priced the melons so that she would make $1.50 profit for each melon.
\n" ); document.write( "Let her price per melon be \"p\".
\n" ); document.write( "EQUATION:
\n" ); document.write( "p = (200/x) + 1.5
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\n" ); document.write( "\n" ); document.write( "When all but 30 had been sold, the manager had recovered her initial investment.
\n" ); document.write( "EQUATION:
\n" ); document.write( "p(x-30) = 200
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\n" ); document.write( "Rearrange the two equations:
\n" ); document.write( "p = (200/x) + 1.5
\n" ); document.write( "p = 200/(x-30)
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\n" ); document.write( "Substitute to solve for \"x\".
\n" ); document.write( "200/(x-30) = (200/x) + 1.5
\n" ); document.write( "Multiply thru by x(x-30) to get:
\n" ); document.write( "200x = 200(x-30) + 1.5x(x-30)
\n" ); document.write( "6000 = 1.5x^2 - 45x
\n" ); document.write( "x^2 - 30x -4000 = 0
\n" ); document.write( "(x- 80)(x+50) = 0
\n" ); document.write( "Positive solution
\n" ); document.write( "x = 80 (original number of melons)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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