document.write( "Question 153236: The manager at Cream of the Crop bought a load of watermelons for $200. She priced the melons so that she would make $1.50 profit for each melon. When all but 30 had been sold, the manager had recovered her initial investment. How many did she buy originally? \n" ); document.write( "
Algebra.Com's Answer #112775 by checkley77(12844)\"\" \"About 
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200=[(200/x)+1.50](x-30)
\n" ); document.write( "200=[(200+1.5x)/x](x-30)
\n" ); document.write( "200x=(200+1.5x)(x-30)
\n" ); document.write( "200x=200x+1.5x^2-6,000-45x
\n" ); document.write( "1.5x^2-45x-6,000=0
\n" ); document.write( "(1.5x-120)(x+50)=0
\n" ); document.write( "1.5x-120=0
\n" ); document.write( "1.5x=120
\n" ); document.write( "x=120/1.5
\n" ); document.write( "x=80 is the number of watermellons bought.
\n" ); document.write( "Proof:
\n" ); document.write( "200=[(200/80)+1.5](80-30)
\n" ); document.write( "200=[2.5+1.5]*50
\n" ); document.write( "200=4*50
\n" ); document.write( "200=200
\n" ); document.write( "
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