document.write( "Question 153241This question is from textbook intermediate algebra
\n" ); document.write( ": on page 58 of the textbook. the problem is a=180-(a-2/n) solve for n.
\n" ); document.write( "this is what i got so far up to point where i am stuck.\r
\n" ); document.write( "\n" ); document.write( "a=180(1-2/n) distribute
\n" ); document.write( "a=180-360/n +360/n
\n" ); document.write( "360/n=180-a -a
\n" ); document.write( "?\r
\n" ); document.write( "\n" ); document.write( "am i doing this right so far? Also im not sure of the next step. After i got to this point i didnt know what to do
\n" ); document.write( "

Algebra.Com's Answer #112772 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
So the equation is \"a=180%281-2%2Fn%29\" ?\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"a=180%281-2%2Fn%29\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28a%29%2F%28180%29=1-2%2Fn\" Divide both sides by 180.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28a%29%2F%28180%29-1=-2%2Fn\" Subtract 1 from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28a-180%29%2F%28180%29=-2%2Fn\" Combine the fractions.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28n%28a-180%29%29%2F%28180%29=-2\" Multiply both sides by \"n\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"n%28a-180%29=-2%28180%29\" Multiply both sides by 180.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"n%28a-180%29=-360\" Multiply\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"n=-360%2F%28a-180%29\" Divide both sides by \"a-180\".
\n" ); document.write( "
\n" );