document.write( "Question 153238: (3u^2v – 2)(4u^2v + 6)\r
\n" ); document.write( "\n" ); document.write( "this is what I got...but to be honest i'm confused a little.\r
\n" ); document.write( "\n" ); document.write( "(3u^2v – 2)(4u^2v + 6)
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\n" ); document.write( " 12u^2v + 26u^2v – 12
\n" ); document.write( " 38u^4v^2 – 12
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Algebra.Com's Answer #112767 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"%283u%5E2v-2%29%284u%5E2v%2B6%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Now let's FOIL the expression.\r
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\n" ); document.write( "\n" ); document.write( "Remember, when you FOIL an expression, you follow this procedure:\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283u%5E2v%29-2%29%28highlight%284u%5E2v%29%2B6%29\" Multiply the First terms:\"%283%2Au%5E2%2Av%29%2A%284%2Au%5E2%2Av%29=12%2Au%5E4%2Av%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283u%5E2v%29-2%29%284u%5E2v%2Bhighlight%286%29%29\" Multiply the Outer terms:\"%283%2Au%5E2%2Av%29%2A%286%29=18%2Au%5E2%2Av\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283u%5E2v%2Bhighlight%28-2%29%29%28highlight%284u%5E2v%29%2B6%29\" Multiply the Inner terms:\"%28-2%29%2A%284%2Au%5E2%2Av%29=-8%2Au%5E2%2Av\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283u%5E2v%2Bhighlight%28-2%29%29%284u%5E2v%2Bhighlight%286%29%29\" Multiply the Last terms:\"%28-2%29%2A%286%29=-12\".\r
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\n" ); document.write( "\n" ); document.write( "\"12%2Au%5E4%2Av%5E2%2B18%2Au%5E2%2Av-8%2Au%5E2%2Av-12\" Now collect every term to make a single expression.\r
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\n" ); document.write( "\n" ); document.write( "\"12%2Au%5E4%2Av%5E2%2B10%2Au%5E2%2Av-12\" Now combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"%283u%5E2v-2%29%284u%5E2v%2B6%29\" FOILs to \"12%2Au%5E4%2Av%5E2%2B10%2Au%5E2%2Av-12\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%283u%5E2v-2%29%284u%5E2v%2B6%29=12u%5E4v%5E2%2B10u%5E2v-12\".
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