document.write( "Question 153182: B 2b
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\n" ); document.write( " b-1 b squared - 1
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Algebra.Com's Answer #112764 by jim_thompson5910(35256)\"\" \"About 
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\"b%2F%28b-1%29%2B%282b%29%2F%28b%5E2-1%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"b%2F%28b-1%29%2B%282b%29%2F%28%28b-1%29%28b%2B1%29%29\" Factor \"b%5E2-1\" to get \"%28b-1%29%28b%2B1%29\". Notice how the LCD is \"%28b-1%29%28b%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28b%2B1%29%2F%28b%2B1%29%29%28b%2F%28b-1%29%29%2B%282b%29%2F%28%28b-1%29%28b%2B1%29%29\" Multiply the first term by \"%28b%2B1%29%2F%28b%2B1%29\". The goal is to get the first denominator equal to the LCD \"%28b-1%29%28b%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28b%28b%2B1%29%29%2F%28%28b-1%29%28b%2B1%29%29%2B%282b%29%2F%28%28b-1%29%28b%2B1%29%29\" Combine the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"%28b%5E2%2Bb%29%2F%28%28b-1%29%28b%2B1%29%29%2B%282b%29%2F%28%28b-1%29%28b%2B1%29%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"%28b%5E2%2Bb%2B2b%29%2F%28%28b-1%29%28b%2B1%29%29\" Add the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"%28b%5E2%2B3b%29%2F%28%28b-1%29%28b%2B1%29%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"b%2F%28b-1%29%2B%282b%29%2F%28b%5E2-1%29=%28b%5E2%2B3b%29%2F%28%28b-1%29%28b%2B1%29%29\" where \"b%3C%3E-1\" or \"b%3C%3E1\"
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