document.write( "Question 153192: I have have an inequality word problem from a worksheet, could someone show me how the problem should be written so I can solve it thanks...
\n" ); document.write( "The sum of a number and 81 is greater than the product of 3 and that number.
\n" ); document.write( "

Algebra.Com's Answer #112716 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The sentence \"The sum of a number and 81 is greater than the product of 3 and that number\" translates to \"x%2B81%3E3x\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2B81%3E3x\" Start with the given inequality.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%3E3x-81\" Subtract \"81\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x-3x%3E-81\" Subtract \"3x\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-2x%3E-81\" Combine like terms on the left side.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%3C%28-81%29%2F%28-2%29\" Divide both sides by \"-2\" to isolate \"x\". note: Remember, the inequality sign flips when we divide both sides by a negative number. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%3C81%2F2\" Reduce.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the answer is \"x%3C81%2F2\" \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Which approximates to \"x%3C40.5\"
\n" ); document.write( "
\n" );