document.write( "Question 153165: Making a round trip from Fairview to Casterville, a distance of 20 miles, a pilot faces a 30mph head wind one way and a 30mph tail wind on the return trip. The return trip takes 45 minutes less than the outbound journey. Find the speed of the plane in still air\r
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document.write( "from Fair/Cast distance=10miles; rate = (r-30); time = t
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document.write( "from Cast/Fair distnace= 10miles; rate = (r+30); time = t -45
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document.write( "the total distance is 20 miles\r
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document.write( "so 10 = t(r-30)
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document.write( " 10 = (r+30)(t-45)\r
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document.write( "the two variables are throwing me off, somethings wrong in my setup??\r
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document.write( "Thanks for your help. \n" );
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Algebra.Com's Answer #112669 by orca(409) ![]() You can put this solution on YOUR website! There is only a small mistake in the second equation. It is the unit of time. \n" ); document.write( "Note that the unit for the speed of the wind is miles/hour. So you need to convert 45 minutes into 3/4 hours \n" ); document.write( "So the simultaneous equations become: \n" ); document.write( "10 = t(r-30) ................(1) \n" ); document.write( "10 = (r+30)(t-3/4) ...........(2)\r \n" ); document.write( "\n" ); document.write( "From equation (1), we have \n" ); document.write( " \n" ); document.write( "Substituting it into equation (2), we have \n" ); document.write( " \n" ); document.write( "Solving for the above equation, we obtain \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |