document.write( "Question 153149: a room's length is 3 feet less than twice its width. the area if the room is 135 square feet. What are the rooms dimensions? \n" ); document.write( "
Algebra.Com's Answer #112655 by orca(409)\"\" \"About 
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Let x be the width of the room, then the length can be expressed in terms of x as 2x - 3.
\n" ); document.write( "Its area in terms of x is x(2x - 3).
\n" ); document.write( "Setting x(2x - 3) = 135, we have
\n" ); document.write( "x(2x - 3) = 135
\n" ); document.write( "Re-arrange the quadratic equation into standard form:
\n" ); document.write( "2x^2 - 3x - 135 = 0
\n" ); document.write( "Solve it by using the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "Here a = 2, b = -3 and c = -135\r
\n" ); document.write( "\n" ); document.write( "So
\n" ); document.write( "\"x+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%2A2%2A%28-135%29+%29%29%2F%282%2A2%29+\"
\n" ); document.write( "=\"%283+%2B-+sqrt%28+9%2B1080+%29%29%2F4\"
\n" ); document.write( "=\"%283+%2B-+sqrt%28+1089%29%29%2F4\"
\n" ); document.write( "=\"%283+%2B-+33%29%2F4\"
\n" ); document.write( "So \"x+=+%283%2B33%29%2F4+=+36%2F4=9\" or \"x+=+%283-33%29%2F4+=+-30%2F4=-7.5\"
\n" ); document.write( "Reject x = -7.5 as the width can not be negative.
\n" ); document.write( "So the solution is x = 9
\n" ); document.write( "Therefore the width is 9ft,the length is 2x - 3=2*9-3=15.
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