document.write( "Question 153149: a room's length is 3 feet less than twice its width. the area if the room is 135 square feet. What are the rooms dimensions? \n" ); document.write( "
Algebra.Com's Answer #112655 by orca(409) ![]() You can put this solution on YOUR website! Let x be the width of the room, then the length can be expressed in terms of x as 2x - 3. \n" ); document.write( "Its area in terms of x is x(2x - 3). \n" ); document.write( "Setting x(2x - 3) = 135, we have \n" ); document.write( "x(2x - 3) = 135 \n" ); document.write( "Re-arrange the quadratic equation into standard form: \n" ); document.write( "2x^2 - 3x - 135 = 0 \n" ); document.write( "Solve it by using the quadratic formula:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Here a = 2, b = -3 and c = -135\r \n" ); document.write( "\n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "So \n" ); document.write( "Reject x = -7.5 as the width can not be negative. \n" ); document.write( "So the solution is x = 9 \n" ); document.write( "Therefore the width is 9ft,the length is 2x - 3=2*9-3=15. \n" ); document.write( " \n" ); document.write( " |