document.write( "Question 153147: I need help on how to set up the word problems. The sum of three is one-hundred twenty-three. the second number is two more than twice the first number . the third is five less than the produce of three and the first number. find the three numbers. I understand the total is 123 I just don't understand the rest can you please help me with the steps if you can't can you tell me a site that I can go to to help me understand. Thank Kary Martin \n" ); document.write( "
Algebra.Com's Answer #112651 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let the 3 numbers be: x, y z \n" ); document.write( ": \n" ); document.write( "Write and equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"The sum of three numbers is one-hundred twenty-three.\" \n" ); document.write( " x + y + z = 123 \n" ); document.write( ": \n" ); document.write( "\" the second number is two more than twice the first number: \n" ); document.write( " y = 2x + 2 \n" ); document.write( ": \n" ); document.write( "\"the third is five less than the product of three and the first number.\" \n" ); document.write( " z = 3x - 5 \n" ); document.write( "; \n" ); document.write( "find the three numbers. \n" ); document.write( ": \n" ); document.write( "Substitute for y and z in the total equation \n" ); document.write( ": \n" ); document.write( "x + (2x+2) + (3x-5) = 123 \n" ); document.write( ": \n" ); document.write( "6x - 3 = 123 \n" ); document.write( ": \n" ); document.write( "6x = 123 + 3 \n" ); document.write( ": \n" ); document.write( "6x = 126 \n" ); document.write( "x = \n" ); document.write( "x = 21 \n" ); document.write( ": \n" ); document.write( "Use the other two equations to find y and z, check the total \n" ); document.write( ": \n" ); document.write( "has this been set up enough for you?? \n" ); document.write( " |