document.write( "Question 153136: If log 2 » 0.301 and log 3 » 0.477, then log 6 » \n" ); document.write( "
Algebra.Com's Answer #112642 by stanbon(75887) ![]() You can put this solution on YOUR website! If log 2 » 0.301 and log 3 » 0.477, then log 6 \n" ); document.write( "-------------------- \n" ); document.write( "log6 = log(2*3) = log2 + log3 = 0.301+0.477 = 0.778151 \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |