document.write( "Question 152809: solve using addition method:\r
\n" ); document.write( "\n" ); document.write( "3x^2-2y^2=-5
\n" ); document.write( "2x^2-y^2=-2\r
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Algebra.Com's Answer #112622 by checkley77(12844)\"\" \"About 
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3x^2-2y^2=-5
\n" ); document.write( "2x^2-y^2=-2 multiply this equation by -2 & add.
\n" ); document.write( "-4x^2+2y^2=4
\n" ); document.write( "3x^2-2y^2=-5
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\n" ); document.write( "x^2+0=-1
\n" ); document.write( "x^2+1=0
\n" ); document.write( "x=0+/-1i (this has complex roots)\r
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