document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22858>Question 22858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5(2-x)/6 = x+6/2   Trying to teach myself algebra from text. If you would do this one step by step, I would really appreciate it. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11262 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since you have denominators, find the LCM (least common multiple) of 6 and 2.<BR>\n" );
document.write( "The LCM is 6.<BR>\n" );
document.write( "Multiply both sides of the equation by the LCM = 6 to get the following:<BR>\n" );
document.write( "5(2-x) = 6x +18<BR>\n" );
document.write( "10-5x = 6x+18<BR>\n" );
document.write( "Add 5x to both sides and subtract 18 from both sides to get:<BR>\n" );
document.write( "11x = -8 <BR>\n" );
document.write( "Divide both sides by 11 to get<BR>\n" );
document.write( "  x = -8/11 </SPAN>\n" );
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