document.write( "Question 153107: simplify:\r
\n" ); document.write( "\n" ); document.write( "(x-5)(x^2-3x-2)
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Algebra.Com's Answer #112610 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"%28x-5%29%28x%5E2-3x-2%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%5E2-3x-2%29-5%28x%5E2-3x-2%29\" Expand.\r
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\n" ); document.write( "\n" ); document.write( " Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3-3%2Ax%5E2-2%2Ax-5%2Ax%5E2%2B15%2Ax%2B10\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3-8%2Ax%5E2%2B13%2Ax%2B10\" Now combine like terms.\r
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\n" ); document.write( "\n" ); document.write( " So \"%28x-5%29%28x%5E2-3x-2%29\" expands to \"x%5E3-8%2Ax%5E2%2B13%2Ax%2B10\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%28x-5%29%28x%5E2-3x-2%29=x%5E3-8%2Ax%5E2%2B13%2Ax%2B10\".
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