document.write( "Question 151818: Wealey invested $6,500 in a mutual fund at a yearly rate of 3 3/4%. If he earned %975 in interest, how long has the money been invested?
\n" ); document.write( "a. 2.5 years
\n" ); document.write( "b. 3 years
\n" ); document.write( "c. 4 years
\n" ); document.write( "d. 4.5 years
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Algebra.Com's Answer #112582 by orca(409)\"\" \"About 
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Simple interest earned (I) can be found by the formula:
\n" ); document.write( "\"I=Prt\"
\n" ); document.write( "where P is the principal, r is the annual interest rate,and t is the number of years that the principal will be invested.
\n" ); document.write( "In this problem:
\n" ); document.write( "P=6500
\n" ); document.write( "r=3 3/4%=3.75%
\n" ); document.write( "I=975
\n" ); document.write( "Substituting into the formula, we have
\n" ); document.write( "975 = 6500*3.75%t
\n" ); document.write( "Solving the equation for t, we obtain:
\n" ); document.write( "975 = 65*3.75*t
\n" ); document.write( "\"t+=+975%2F%2865%2A3.75%29\"
\n" ); document.write( "t = 4
\n" ); document.write( "So choose option C.\r
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