document.write( "Question 22863: How can you use a quadratic formula to solve the following equations?\r
\n" ); document.write( "\n" ); document.write( "0 = x^2 + x - 20\r
\n" ); document.write( "\n" ); document.write( "0 = x^2 - 5x + 6
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Algebra.Com's Answer #11257 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I'm going to assume you want to solve these equations separately;
\n" ); document.write( "i.e. you do not want to solve them as a system of two quadratic
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\n" ); document.write( "If so you use the quadratic formula to solve the 2nd one as follows:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-5x%2B6+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-5%29%5E2-4%2A1%2A6=1\".
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\n" ); document.write( " Discriminant d=1 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--5%2B-sqrt%28+1+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-5%29%2Bsqrt%28+1+%29%29%2F2%5C1+=+3\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-5%29-sqrt%28+1+%29%29%2F2%5C1+=+2\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-5x%2B6\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-5x%2B6+=+1%28x-3%29%2A%28x-2%29\"
\n" ); document.write( " Again, the answer is: 3, 2.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-5%2Ax%2B6+%29\"
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