document.write( "Question 153069: The length of a retangle is twice the width. The area is 392 yards^2. Find the length and width. \r
\n" ); document.write( "\n" ); document.write( "I tried to solve this problem, but I am not sure if I did it correctly. \r
\n" ); document.write( "\n" ); document.write( "A=196(95)-(95)
\n" ); document.write( "=18620 - 9025
\n" ); document.write( "=9595\r
\n" ); document.write( "\n" ); document.write( "w=95
\n" ); document.write( "l=95
\n" ); document.write( "
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Algebra.Com's Answer #112533 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
DON'T KNOW WHERE YOU GET 30? BUT IT ISN'T IN THE PROBLEM NOR IN THE ANSWER.
\n" ); document.write( "THE ANSWER IS THE LENGTH IS 28 YDS & THE WIDTH 14 YDS. THIS GIVES AN AREA=392.
\n" ); document.write( "LW=AREA
\n" ); document.write( "L=2W
\n" ); document.write( "2W*W=392
\n" ); document.write( "2W^2-392=0
\n" ); document.write( "2(W^2-196)=0
\n" ); document.write( "2(W+14)(W-14)=0
\n" ); document.write( "W-14=0
\n" ); document.write( "W=14 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=2*14=28 FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "28*14=392
\n" ); document.write( "392=392\r
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