document.write( "Question 153024: Fundraising. The St. Mark’s Community Barbecue served 250 dinners. A child’s plate cost $3.50 and an adult’s plate cost $7.00. A total of $1347.50 was collected. How many of each type of plate was served?\r
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Algebra.Com's Answer #112520 by orca(409)\"\" \"About 
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Let x be the number of children.
\n" ); document.write( "Let y be the number of adults.
\n" ); document.write( "As the total number of dinners is 250, we have:
\n" ); document.write( "x + y = 250 ...................(1)
\n" ); document.write( "The amount of money from children: 3.5x
\n" ); document.write( "The amount of money from adults: 7y.
\n" ); document.write( "As the total is 1347.5,we have:
\n" ); document.write( "3.5x + 7y = 1347.5 ............(2)
\n" ); document.write( "Solving equations (1) and (2) simultaneously, we obtain:
\n" ); document.write( "x = 115
\n" ); document.write( "y = 135
\n" ); document.write( "So the numbers of children and adults are 115 and 135 respectively.
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\n" ); document.write( "How to solve
\n" ); document.write( "x + y = 250 .................(1)
\n" ); document.write( "3.5x + 7y = 1347.5...........(2)
\n" ); document.write( "From (1), we get x = 250 - y. Substitute it into equation (2), we obtain:
\n" ); document.write( "3.5(250 - y) + 7y = 1347.5
\n" ); document.write( "875 - 3.5y + 7y = 1347.5
\n" ); document.write( "875 + 3.5y = 1347.5
\n" ); document.write( "3.5y = 472.5
\n" ); document.write( "y = 135
\n" ); document.write( "x= 250 - y = 115\r
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