document.write( "Question 153063: Find all the solutions of \"+x%5E3%2B3x%5E2%2B3x%2B2=0+\" given that -2 is a root
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Algebra.Com's Answer #112519 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Since -2 is a root then (x+2) is one factor of the equation.
\n" ); document.write( "You can divide the original polynomial by (x+2) to find the quadractic factor.
\n" ); document.write( "\"%28x%5E3%2B3x%5E2%2B3x%2B2%29%2F%28x%2B2%29=x%5E2%2Bx%2B1\"
\n" ); document.write( "Now find the roots of \"x%5E2%2Bx%2B1\".
\n" ); document.write( "\"x%5E2%2Bx%2B1=0\"
\n" ); document.write( "Using the quadratic formula,
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+%281%29%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1-4+%29%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+-3+%29%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+3+%29i%29%2F%282%29+\"
\n" ); document.write( "The solutions are \"x=-2\" and \"x+=+%28-1+%2B-+sqrt%28+3+%29i%29%2F%282%29+\".
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