document.write( "Question 153060: Tickets to a local movie were sold at $6 for adults and $4.50 for students. If 63 tickets were sold for a total of $358.50, how many adult tickets were sold? \n" ); document.write( "
Algebra.Com's Answer #112517 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let x=# of adults and y=# of students\r
\n" ); document.write( "\n" ); document.write( "Since the \"63 tickets were sold\", this means that the first equation is \"x%2By=63\"\r
\n" ); document.write( "\n" ); document.write( "Also, because the tickets \"were sold at $6 for adults and $4.50 for students\" and they collected a \"total of $358.50\", this means that the second equation is \"6x%2B4.5y+=+358.5\"\r
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\n" ); document.write( "\n" ); document.write( "\"60x%2B45y+=+3585\" Multiply every term in the second equation by 10 to move the decimal point one spot to the right\r
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\n" ); document.write( "\n" ); document.write( "So we have the system of equations: \r
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\n" ); document.write( "\n" ); document.write( "\"system%28x%2By=63%2C60x%2B45y=3585%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.\r
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\n" ); document.write( "\n" ); document.write( "So let's isolate y in the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=63\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=63-x\" Subtract \"x\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x%2B63\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "Since \"y=-x%2B63\", we can now replace each \"y\" in the second equation with \"-x%2B63\" to solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"60x%2B45highlight%28%28-x%2B63%29%29=3585\" Plug in \"y=-x%2B63\" into the first equation. In other words, replace each \"y\" with \"-x%2B63\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"60x%2B%2845%29%28-1%29x%2B%2845%29%2863%29=3585\" Distribute \"45\" to \"-x%2B63\"\r
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\n" ); document.write( "\n" ); document.write( "\"60x-45x%2B2835=3585\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"15x%2B2835=3585\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"15x=3585-2835\"Subtract 2835 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"15x=750\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28750%29%2F%2815%29\" Divide both sides by 15 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=50\" Divide\r
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\n" ); document.write( "\n" ); document.write( "-----------------First Answer------------------------------\r
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\n" ); document.write( "\n" ); document.write( "So the first part of our answer is: \"x=50\"\r
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\n" ); document.write( "\n" ); document.write( "Since we know that \"x=50\" we can plug it into the equation \"y=-x%2B63\" (remember we previously solved for \"y\" in the first equation).\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x%2B63\" Start with the equation where \"y\" was previously isolated.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-%2850%29%2B63\" Plug in \"x=50\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-50%2B63\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y=13\" Combine like terms \r
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\n" ); document.write( "\n" ); document.write( "-----------------Second Answer------------------------------\r
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\n" ); document.write( "\n" ); document.write( "So the second part of our answer is: \"y=13\"\r
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\n" ); document.write( "\n" ); document.write( "-----------------Summary------------------------------\r
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\n" ); document.write( "\n" ); document.write( "So our answers are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=50\" and \"y=13\"\r
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\n" ); document.write( "\n" ); document.write( "So there were 50 adults and 13 students
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