document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=153031>Question 153031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -1^-2 = @ The Order of Operations requires exponents to be evaluated first, and exponents only apply to whatever they are immediately attached to; subtraction (from 0) comes last. You have to also recognize that the negative exponent simply requires an inverse of the value. <BR>\n" );
document.write( "a. 1<BR>\n" );
document.write( "b.-1<BR>\n" );
document.write( "c. 2<BR>\n" );
document.write( "d. None of the above </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #112503 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=112503\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -1^-2 = @ The Order of Operations requires exponents to be evaluated first, and exponents only apply to whatever they are immediately attached to; subtraction (from 0) comes last. You have to also recognize that the negative exponent simply requires an inverse of the value. <BR>\n" );
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document.write( "1st step: 1^-2 = 1/1^2 = 1/1 = 1<BR>\n" );
document.write( "2nd step: take the negative to get -1<BR>\n" );
document.write( "Ans: b<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "a. 1<BR>\n" );
document.write( "b.-1<BR>\n" );
document.write( "c. 2<BR>\n" );
document.write( "d. None of the above </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );